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6t^2+6t-36=0
a = 6; b = 6; c = -36;
Δ = b2-4ac
Δ = 62-4·6·(-36)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-30}{2*6}=\frac{-36}{12} =-3 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+30}{2*6}=\frac{24}{12} =2 $
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